I am a beginner in Jasmine
and I was wondering, why the default value for allowRespy
is set to false
?
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Bohdan Forostianyi
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1 Answers
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I found this answer, where explained that jasmine.spyOn()
always returns the first created spy, so I assume that the reason for flag it to prevent usage of mock with state.
I can come out with a simplified example where such a behavior could be problematic:
describe("TestedService", () => {
const testedService = TestBed.inject(TestedService) // configuration is ommited for simplicity
it("calls foo only once", () => {
const fooSpy = spyOn(testedService, 'foo')
testedService.doAction()
expect(fooSpy).toHaveBeenCalledOnce()
fooSpy = spyOn(testedService, 'foo') // creating new spy to check if it will be called for the second time
testedService.doAction()
expect(fooSpy).not.toHaveBeenCalledOnce() // fails the test because it still points to the same spy,that was called few moments later.
})
})
Another, more realistic example of problematic behavior is when you want to reset a spy
used in your test by creating a new spy
with spyOn
function, but instead of it you will not be created and spy
with old state will be used.
Example
describe("TestedService", () => {
beforeEach(() => {
TestBed.inject(TestedService) // configuration is ommited for simplicity
spyOn(TestedService, 'foo').and.returnValue(100)
})
....
it('tests TestedService behavior when foo returns undefined', () => {
spyOn(TestedService, 'foo') // expect it to set spy return value to undefined,
but it don't, so the test below does not tests behavior when foo returns undefined
.....
})
})
Other examples and corrections would be appreciated!

Bohdan Forostianyi
- 121
- 2
- 11