Split list into an n x length matrix

Question

Assuming a list as below:

Y= [-0.0, -0.0, -0.0, -0.0, -0.0, -0.0, 4.0, 4.0, -0.0, 2.0, -0.0, -0.0, 4.0, -0.0, -0.0, -0.0, -0.0, -0.0, 4.0, 2.0, -0.0, -0.0, -0.0, 4.0, 2.0, 4.0, -0.0, -0.0, -0.0, -0.0, 4.0, -0.0, -0.0, -0.0, -0.0, -0.0, -0.0, -0.0, -0.0, -0.0, -0.0, 4.0, -0.0, -0.0, 2.0, -0.0, -0.0, -0.0, -0.0, -0.0]

How this list could be converted to a matrix for each n number. let's say set n=10, the matrix or array is supposed to look like below:

Example of expected output

Cheers,

Does this answer your question? [How do you split a list into evenly sized chunks?](https://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks) — SuperStormer, Jul 22 '21 at 00:55
Do you want a dataframe with `n_i` columns and `row_j` rows? — Carmoreno, Jul 22 '21 at 01:55

emremrah · Accepted Answer · 2021-07-22T01:01:59.920

This should do the job. This creates a lists of list though.

step_size = 10
steps = range(0, len(Y), step_size)

y = [Y[step:step + step_size] for step in steps]

If you want an array:

import numpy as np

n = 10

y = np.array(Y).reshape(-1, n)

Yields:

[[-0. -0. -0. -0. -0. -0.  4.  4. -0.  2.]
 [-0. -0.  4. -0. -0. -0. -0. -0.  4.  2.]
 [-0. -0. -0.  4.  2.  4. -0. -0. -0. -0.]
 [ 4. -0. -0. -0. -0. -0. -0. -0. -0. -0.]
 [-0.  4. -0. -0.  2. -0. -0. -0. -0. -0.]]

score -1 · Answer 2 · answered Jul 22 '21 at 00:58

-1

Hi what you can do is

list = [ [0,0,0,0,0,0,0,0,0,0,0,],[....],...,[...]] These are nested list where each internal list is a row and 1colume

answered Jul 22 '21 at 00:58

new_to_code

37
1
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In java they are called mulitdemtional array – new_to_code Jul 22 '21 at 00:59
You can use a loop to make a matrix – new_to_code Jul 22 '21 at 00:59

Split list into an n x length matrix

2 Answers2