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This is the code for sorting a list without any method. I had entered a print statement in the for loop to print the values of a and l.

l,a=(input("enter terms separate with ','\n")).split(','),"5"
def so(m,n,b=0):
    try: return (so(m,n,b+1) if(m[b]==n[b]) else [m,n] if(ord(m[b])<ord(n[b])) else [n,m])
    except: return [m,n] if(b==len(m)) else [n,m]
while(a!=l):
    print(a," is assigned ",l)
    a=l
    for i in range((len(l)-1)):
        l[i],l[i+1]=so(l[i],l[i+1])[0],so(l[i],l[i+1])[1]
        print(l,i,a)

I accept that I have written a=l in the while loop, but the while loop is executed only once. I knew it by inserting a print statement inside the while loop.

After every step in the for loop, a has the same value as l which is not defined anywhere. Also, I didn't assign a or l to any value in the function.

mkrieger1
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Learn-Fun-Done
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1 Answers1

0
while(a!=l):
    print(a," is assigned ",l)
    a=l
    for i in range((len(l)-1)):
        l[i],l[i+1]=so(l[i],l[i+1])[0],so(l[i],l[i+1])[1]
        print(l,i,a)

this is how it appears in my IDE.

when you write a=l, python does not create a new variable a and assign it values. it just creates a reference to l.

you can check it here

iamtrappedman
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