this code below is return a very strange result. It should return 0.0008, but is return 8.202154101077051E-4. Can anyone help me to solve this?
double d1 = 0.0099;
double d2 = 12.0700;
double d3 = d1/d2;
System.out.println(d3);
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DevYeah
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5The output is indeed about 0.0008, [just in a different format](https://en.wikipedia.org/wiki/Scientific_notation#E_notation). – Sweeper Jul 22 '21 at 12:52
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Format it if you don't like it. See `String.format` – g00se Jul 22 '21 at 12:53
1 Answers
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Explanation
It should return 0.0008
It does.
"E" is a format for numbers that are either very big or very close to 0. If an E(value) stands behind a number, that basically means "take this number and multiply it by 10 ^ value".
If you take 8.202154101077051 x 10 ^ -4, you will get 0.0008202154101077051, which is approximatly 0.0008.
Solution
How you can format numbers when printing them out is explained in this stackoverflow answer.
Cactusroot
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