Array check Empty or Null by all properties in object

Question

const data = [

{
 name: "Kris",
 Tel: 000000,
 address:""
},
{
 name: "Mark",
 Tel: 111111,
 address:"USA"
},
{
 name: "Charie",
 Tel: null,
 address:""
},

]

I want to find() empty prop in this array if i has find empty or null i want to return true and break to return so i dont' know how

expect: boolean type for return

from now i use

  const checkEmtry = () => data.forEach(e => Object.values(e).find(x => (x === null) || x === ''  ) )

Please clarify the question... What is the desired output ? Object index in array ? Do you want to find all or just the first object ? — nip, Jul 25 '21 at 15:17
`forEach` will always return `undefined`. Consider using `every` or `some`, whichever is more appropriate? — evolutionxbox, Jul 25 '21 at 15:20
to go a bit further from evolutionxbox's comment, it may be that you want to use `map` if you want every result. Anyway, this question should be clarified _a lot_ IMHO. For instance, you could give output expected data — Ulysse BN, Jul 25 '21 at 15:29
Does this answer your question? [How to determine if Javascript array contains an object with an attribute that equals a given value?](https://stackoverflow.com/questions/8217419/how-to-determine-if-javascript-array-contains-an-object-with-an-attribute-that-e) — pilchard, Jul 25 '21 at 15:48

score 4 · Accepted Answer · edited Jul 25 '21 at 15:29

I think you're looking for the some method (instead of forEach and find), which calls a callback for each element in the array and stops the first time the callback returns true.

const checkEmtry = () => data.some(e => Object.values(e).some(x => x === null || x === ""));
// −−−−−−−−−−−−−−−−−−−−−−−−−−−^^^^−−−−−−−−−−−−−−−−−−−−−−−^^^^

Live Example:

const data = [
    {
        name: "Kris",
        Tel: 000000,
        address:""
    },
    {
        name: "Mark",
        Tel: 111111,
        address:"USA"
    },
    {
        name: "Charie",
        Tel: null,
        address:""
    },
];

const checkEmtry = () => data.some(e => Object.values(e).some(x => x === null || x === ""));

console.log(checkEmtry()); // true

To make the function more generally useful, you might accept the array to check as a parameter:

const checkEmtry = (data) => data.some(e => Object.values(e).some(x => x === null || x === ""));
// −−−−−−−−−−−−−−−−−^^^^

Side note: I wasn't sure whether you meant checkEntry or checkEmpty so I left it checkEmtry above, but you probably want to change the m or the t.

muhammed ikinci · Answer 2 · 2021-07-25T15:29:31.100

const data = [

{
 name: "Kris",
 Tel: 000000,
 address:""
},
{
 name: "Mark",
 Tel: 111111,
 address:"USA"
},
{
 name: "Charie",
 Tel: null,
 address:""
},

]

function deepChecker(data) {
    let checkFilter = data.filter((d) => {
        return Object.values(d).filter((f) => { return f != "" && f != null }).length == Object.values(d).length
    })

    return data.length == checkFilter.length
}
console.log(deepChecker(data))

Array check Empty or Null by all properties in object

2 Answers2