Sort dictionary as per length of values

Question

d={
    1:[1,2,3,4],
    2:[5,4],
    3:[5,6,7]
}

Given a dictionary, we need to sort the dictionary as per the length of values (in this case, as per length of lists)

Output should be as below:

{1:[1,2,3,4],3:[5,6,7],2:[5,4]}

Please help me with the code

`d = {k: v for k, v in sorted(d.items(), key=lambda t: -len(t[1]))}` — Samwise, Jul 26 '21 at 15:12
Does this answer your question? [How do I sort a dictionary by value?](https://stackoverflow.com/questions/613183/how-do-i-sort-a-dictionary-by-value) — crissal, Jul 26 '21 at 15:12
Hi Samwise, Is it possible to sort the list values also at the same time? — Harshita, Jul 26 '21 at 15:22
Harshita: Sure it is, but that's not the question you asked. — martineau, Jul 26 '21 at 15:40

score 0 · Answer 1 · answered Jul 26 '21 at 15:14

0

Easy way if you are sure that your keys will be integers:

d = {key: value for key, value in sorted(d.items())}

answered Jul 26 '21 at 15:14

Amir Afianian

1 Answers1