How to round float to certain amount of decimal places Python

Question

I have a randomly generated float from the random library, and I want to shorten it to any number of places, based on some other number.

Example:

input = 4.06098152

processing the number, rounding to thousandths place

output = 4.061

How would I do this?

Realize that even with perfect rounding, some decimal numbers can't be exactly represented as `real`: [Is floating point math broken?](https://stackoverflow.com/q/588004/5987) — Mark Ransom, Jul 28 '21 at 17:40
I'm curious what you found when you searched for "python rounding". — Mark Ransom, Jul 28 '21 at 17:42

score 2 · Accepted Answer · 2021-07-28T17:35:01.240

2

You can use the built in round function: The second argument in the paranthesis gives the amount of digits to round off

x=input("Enter a decimal number: ")
print(round(float(x),3))

edited Jul 28 '21 at 17:35

answered Jul 28 '21 at 17:24

1 Answers1