Check if dates in array contains a date later than the current date

Question

I have an array of date object:

const dates = [
  '2021-11-01T19:49:08.678Z',
  '2021-11-01T20:13:27.954Z',
  '2021-08-31T19:15:16.452Z',
  '1983-04-16T20:18:39.802Z',
  '2022-02-02T20:26:14.992Z',
  '2022-02-02T20:30:36.374Z',
  '2022-02-02T20:33:09.266Z',
  '2022-02-02T20:35:34.615Z',
  '2022-02-02T20:44:19.131Z',
  '2022-02-02T20:48:17.274Z'
]

I want to check if at least one of the dates inside the array is later than the current date (if there is any date which has not reached yet return true, if all of them past return false)

Does this answer your question? [Check if date is in the past Javascript](https://stackoverflow.com/questions/8305259/check-if-date-is-in-the-past-javascript) — Pedro Henrique, Jul 31 '21 at 20:08

Spectric · Answer 1 · 2021-07-31T21:10:25.703

3

Use Array#some to parse each date and the > operator to check whether the date is later than the current date.

const arr = [
  '2021-11-01T19:49:08.678Z',
  '2021-11-01T20:13:27.954Z',
  '2021-08-31T19:15:16.452Z',
  '1983-04-16T20:18:39.802Z',
  '2022-02-02T20:26:14.992Z',
  '2022-02-02T20:30:36.374Z',
  '2022-02-02T20:33:09.266Z',
  '2022-02-02T20:35:34.615Z',
  '2022-02-02T20:44:19.131Z',
  '2022-02-02T20:48:17.274Z'
]

const hasPassed = arr.some(e => new Date(e) > new Date);
console.log(hasPassed);

edited Jul 31 '21 at 21:10

answered Jul 31 '21 at 20:08

Spectric

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This is not working... it only compares dates not time.. – Sara Ree Aug 01 '21 at 13:45

score 1 · Answer 2 · answered Jul 31 '21 at 20:08

You can use Array.prototype.some for this:

const dates = [
    '2021-11-01T19:49:08.678Z',
    '2021-11-01T20:13:27.954Z',
    '2021-08-31T19:15:16.452Z',
    '1983-04-16T20:18:39.802Z',
    '2022-02-02T20:26:14.992Z',
    '2022-02-02T20:30:36.374Z',
    '2022-02-02T20:33:09.266Z',
    '2022-02-02T20:35:34.615Z',
    '2022-02-02T20:44:19.131Z',
    '2022-02-02T20:48:17.274Z',
];

// If they're strings
console.log(dates.some(d => new Date(d).valueOf() > Date.now()));

const asDates = dates.map(d => new Date(d));
// If they're actual Date objects
console.log(asDates.some(d => d.valueOf() > Date.now()));

const dates2 = [
    '1983-04-16T20:18:39.802Z',
];

console.log(dates2.some(d => new Date(d).valueOf() > Date.now()));

const asDates2 = dates2.map(d => new Date(d));
console.log(asDates2.some(d => d.valueOf() > Date.now()));

score 1 · Answer 3 · answered Jul 31 '21 at 20:11

Array.find should be sufficient for your problem I suppose

const referenceDate = new Date();
console.log([
  `2021-11-01T19:49:08.678Z`,
  `2021-11-01T20:13:27.954Z`,
  `2021-08-31T19:15:16.452Z`,
  `1983-04-16T20:18:39.802Z`,
  `2022-02-02T20:26:14.992Z`,
  `2022-02-02T20:30:36.374Z`,
  `2022-02-02T20:33:09.266Z`,
  `2022-02-02T20:35:34.615Z`,
  `2022-02-02T20:44:19.131Z`,
  `2022-02-02T20:48:17.274Z`
].find(d => new Date(d) > referenceDate)
)

Check if dates in array contains a date later than the current date

3 Answers3