I have a string in python.
str1 = "hello\n1hello123\n2yahoo"
I would like to split this with \n[integer value] to get a list that looks like: [hello, hello123, yahoo]
Can anyone please help?
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2Could you not `.split('\n')` and then post-process from there? – Jerrybibo Aug 02 '21 at 17:53
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See https://stackoverflow.com/questions/743806/how-to-split-a-string-into-a-list – Andrew McClement Aug 02 '21 at 17:54
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2https://www.mycompiler.io/view/75Q4Vb7 check this out – Mr.P Aug 02 '21 at 18:00
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Refer docs on `re.split` – OneCricketeer Aug 02 '21 at 18:03
2 Answers
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As someone who goes too far in avoiding regular expressions (avoiding them whenever possible rather than simply avoiding them when they are inappropriate), I would lean towards splitting on \n and processing the resulting list element by element:
from string import digits
result = [x.lstrip(digits) for x in str1.split("\n")]
If you are less regex-averse than I, and as recommended in the comments,
from re import split
from string import digits
results = split(f'\n[{digits}]*', str1)
chepner
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regular expression package
enter code here
str1 = "hello\n1hello123\n2yahoo"
import re
print(re.split(r"\n[1-9]", str1))
