Why do we have to put the range of iteration of for loop as range(0,len(list)), instead of range( 0,len(list)-1 )

Question

n = [3, 5, 7]

def print_list(x):
    for i in range(0, len(x)):
        print x[i]
        print i

print_list(n)

I thought since the program is iterating through the index, having the range as len(list) would be out of range. However, this is apparently the correct way, and I'm not really sure why. Can somebody explain?

See e.g. https://docs.python.org/3/library/stdtypes.html#typesseq-range - `range` isn't inclusive of the `stop` value. — jonrsharpe, Aug 03 '21 at 08:40
python's `range` gets elements as `[a,b,c,d...)` which menas the last element won't make part of it — Ivan, Aug 03 '21 at 08:40

Kaushal Sharma · Answer 1 · 2021-08-03T08:44:05.873

0

The range() function returns a sequence of numbers, starting from 0 by default, and increments by 1 (by default), and stops when it reaches the specified number.

https://docs.python.org/3/library/stdtypes.html#range

edited Aug 03 '21 at 08:44

answered Aug 03 '21 at 08:40

Kaushal Sharma

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add reference to the range() function in your answer – Wahalez Aug 03 '21 at 08:40
1

It stops when it reaches the specified number – Achille G Aug 03 '21 at 08:41
OP is asking on why last number is "not used" – Ivan Aug 03 '21 at 08:42
@John123 think of it like you are specifying the number of elements as the parameter. range(3) will return 0,1,2 , i.e. 3 elements. It doesn't return the number specified in the parameter. – Kaushal Sharma Aug 03 '21 at 08:52

Why do we have to put the range of iteration of for loop as range(0,len(list)), instead of range( 0,len(list)-1 )

1 Answers1