I want to print test outside the .then and .db.get. Is there a way to do it?
db.get("key1").then(value => {
var test = value;
});
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2Not really, no. – evolutionxbox Aug 06 '21 at 01:02
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2Does this answer your question? [How to return the response from an asynchronous call](https://stackoverflow.com/questions/14220321/how-to-return-the-response-from-an-asynchronous-call) – evolutionxbox Aug 06 '21 at 01:03
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1Its not even a "not really", doing anything other than awaiting or thenning leaves you open to a race condition which is never fun to debug. – zero298 Aug 06 '21 at 01:05
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@zero298 or leaving you with having to set arbitrary timeouts to wait for the variable to be ready. – evolutionxbox Aug 06 '21 at 01:06