how to handle exception without exiting from function?

Question

def clear_environment():
    delete_deploy_job() # could throw an exception
    delete_filler_job() # could throw an exception
    delete_project() # could throw an exception
    delete_pods() # could throw an exception

I need all these functions to execute, even if one of them throws an exception
Which is the best approach for this ?
Thanks in advance

Either put a `try...except` around each function call, or (better) put a `try...except` in each function... better because inside from the function you can provide a more informative log message. — BoarGules, Aug 06 '21 at 11:04
Does this answer your question? [How to properly ignore exceptions](https://stackoverflow.com/questions/730764/how-to-properly-ignore-exceptions) — Dan Gardner, Aug 06 '21 at 12:41

score 4 · Accepted Answer · answered Aug 06 '21 at 11:03

4

You could try them in a loop:

def clear_environment():
    funcs = [delete_deploy_job, delete_filler_job, delete_project, delete_pods]
    for f in funcs:
        try:
            f()
        except Exception:
            pass

answered Aug 06 '21 at 11:03

quamrana

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I'd add something like `log.exception('Cleanup %s failed', f.__name__)` to the `except`. – bereal Aug 06 '21 at 11:04

how to handle exception without exiting from function?

1 Answers1