Finding array length in function

Asked Aug 06 '21 at 12:05

Active Aug 06 '21 at 12:05

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I'm trying to build a function that returns the length of an array in C++, So far I made the function:

int solution(int A[]) { return (sizeof(A)/sizeof(A[0]));

But I'm given the error: Dividing sizeof a pointer by another value,

asked Aug 06 '21 at 12:05

Zedd7

3

`template int solution(int (&A)[N]) { return N; }`? – Jarod42 Aug 06 '21 at 12:08
1

Switch to a `std::vector` or `std::array` then just use `.size()` – Cory Kramer Aug 06 '21 at 12:08

0 Answers0