How to output a table from the list

Question

Now I have a list:

TIME: ['15:10', '16:40', '16:50', '18:20', '18:30', '20:00']

I need to output using a loop like this:

1. 15:10 - 16:40
2. 16:50 - 18:20
3. 18:30 - 20:00

@Barmar OP's looking for *non-overlapping* chunks. Here's a duplicate for that: [How do you split a list into evenly sized chunks?](https://stackoverflow.com/q/312443/4518341) — wjandrea, Aug 06 '21 at 17:39

score 0 · Accepted Answer · answered Aug 06 '21 at 17:36

A nice combination of enumarate, zip and slicing

values = ['15:10', '16:40', '16:50', '18:20', '18:30', '20:00']
for i, (start, end) in enumerate(zip(values[::2], values[1::2]), 1):
    print(f"{i}. {start} - {end}")

1. 15:10 - 16:40
2. 16:50 - 18:20
3. 18:30 - 20:00

score 0 · Answer 2 · answered Aug 06 '21 at 17:37

0

Try this:

TIME= ['15:10', '16:40', '16:50', '18:20', '18:30', '20:00']
for i in range(len(TIME)-1,2):
    print(f'{i+1}. {TIME[i]} - {TIME[i+1]}')

answered Aug 06 '21 at 17:37

score 0 · Answer 3 · answered Aug 06 '21 at 17:37

0

You can use enumerate, zip, and iterate the corresponding items and print the values.

for i,v in enumerate(zip(TIME[::2], TIME[1::2]), 1):
    print(f'{i}. {" - ".join(v)}')
    
1. 15:10 - 16:40
2. 16:50 - 18:20
3. 18:30 - 20:00

answered Aug 06 '21 at 17:37

ThePyGuy

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How to output a table from the list

3 Answers3