How to sort javascript array of objects, based upon a key

Question

How can I sort this array based upon id ?

const arr = [{
    "id": 38938888,
    "subInternalUpdates": true,
  },
  {
    "id": 38938887,
    "subInternalUpdates": true
  },
  {
    "id": 38938889,
    "subInternalUpdates": true
  }
];
const sorted_by_name = arr.sort((a, b) => a.id > b.id);
console.log(sorted_by_name);

expected output

const arr = [
  {
    "id": 38938887,
    "subInternalUpdates": true
  },
{
    "id": 38938888,
    "subInternalUpdates": true,
  },
  {
    "id": 38938889,
    "subInternalUpdates": true
  }
];

your expected results matches ... though, I'd use `a.id - b.id` instead — Bravo, Aug 11 '21 at 06:49

score 5 · Accepted Answer · answered Aug 11 '21 at 06:51

Much better return a.id - b.id when you order the array:

const arr = [{
    "id": 38938888,
    "subInternalUpdates": true,
  },
  {
    "id": 38938887,
    "subInternalUpdates": true
  },
  {
    "id": 38938889,
    "subInternalUpdates": true
  }
];
const sorted_by_name = arr.sort((a, b) => {
   return a.id - b.id;
});
console.log(sorted_by_name);

score 2 · Answer 2 · answered Aug 11 '21 at 06:49

You can directly compare using a-b, otherwise, if you're comparing the values, you need to return -1, 0 or 1 for sort to work properly

const arr = [{
    "id": 38938888,
    "subInternalUpdates": true,
  },
  {
    "id": 38938887,
    "subInternalUpdates": true
  },
  {
    "id": 38938889,
    "subInternalUpdates": true
  }
];
const sorted_by_name = arr.sort((a, b) => a.id - b.id);
console.log(sorted_by_name);

How to sort javascript array of objects, based upon a key

2 Answers2