I have a web app on Django platform.
I have a method within views.py:
def task():
print("my task")
how can I run it every day once?
I need a very simple solution and it should be independent of other tasks (parallel).
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Is this function registered as a view in `urls.py` or is it just a normal python function? If the later, then it should be in a different file. – Code-Apprentice Aug 11 '21 at 17:54
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Try using `django-celery-beat` [link](https://github.com/celery/django-celery-beat) – Prakhar Aug 11 '21 at 17:56
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not registered in urls – Nesi Aug 11 '21 at 18:16
1 Answers
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There are several libraries that help facilitate periodic tasks. Two that I have used are celery and django-q.
Celery is a general python task manager. Using it with django requires additional libraries to bring them together. Where as django-q is specifically for django projects.
On a side note, if the task() function is not an actual view, then it belongs in a separate file other than views.py.
Code-Apprentice
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is there another simpler solution? Celery is too complex for a simple task – Nesi Aug 11 '21 at 18:17
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@NasimiEldarov Django-Q is less complex than celery in my experience, but I find it's documentation less robust, especially in the introduction/overview area. As an aside, the complexity of the task is entirely independent of the complexity of scheduling it to run. – Code-Apprentice Aug 11 '21 at 20:40