how to access array offset on value of type null

Question

Warning: Trying to access array offset on value of type null in C:\xampp\htdocs\MINI PROJECT\CDP\presentationlayer\doctor\index2.php on line 38

The error above is what i get when i click on the doctor's info on my website and it is same for 41,44,47,50.

below is the code;

<?php include ('../../datalayer/server.php'); ?>
<!DOCTYPE html>
<html lang="en" dir="ltr">
  <head>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Doctor</title>
    <link rel="stylesheet"  href="style3.css">
    <link href="https://fonts.googleapis.com/css2?family=Alfa+Slab+One&family=Open+Sans:wght@300&display=swap" rel="stylesheet">
</head>

<header>
    <h1 >Doctor<span>Patient</span></h1>
        <nav>

        <ul>
            <li><a href="index2.php">MyInfo</a></li>
            <li><a href="doctorapp.php">My Appointments</a></li>
            <li><a href=" searchpatient.php">Search Patient</a></li>
            <li><a href="add.php">Add Description</a></li>
            <li><a href="../../consultant/consultant.html">Logout</a></li>
        </ul>
    </nav>
</header>
<body>

    <div class="header">
    <h2>My Information</h2>
</div>
<form method="post" action="index2.php" class="info">
<div class="Dcontent">


    <label>ID: <?php echo "" .isset($_SESSION['DoctorID']);?></label>

           <br>
           <br>
          38. <label> Email : <?php echo $colD['email']; ?></label>
                   <br>
           <br>
          41. <label> Name : <?php echo $colD['Doctorname']; ?></label>
                   <br>
           <br>
          44. <label> Address : <?php echo $colD['Address']; ?></label>
                   <br>
           <br>
          47. <label> Contact Number : <?php echo $colD['ContactNumber']; ?></label>
                   <br>
           <br>
          50. <label> Specialized In : <?php echo $colD['category']; ?></label>
                   <br>
           <br>

  </div>
</form>
<!--<div class="footer">
    <div id="copyright"><small>© 2021 Kwame Nkrumah University of Science & Technology.</small></div>
</div>-->
</body>
</html>

and line 38 in index2.php is...? You've provided a totally irrelevant code from a wrong file.. — vanowm, Aug 12 '21 at 00:27
Does this answer your question? [Trying to access array offset on value of type null](https://stackoverflow.com/questions/59322150/trying-to-access-array-offset-on-value-of-type-null) — Martin Zeitler, Aug 12 '21 at 00:39
Obviously, you may want to define variable `$colD`, to begin with ... before being able to access any element within that `array`... `$colD = [];` would at least give you an array (which has no elements). Based on the footer notice ...is this your homework? — Martin Zeitler, Aug 12 '21 at 00:51
$userprofile=isset($_SESSION['UserID']); $query="SELECT * FROM patients WHERE UserID=('$userprofile')"; $result= mysqli_query($mysqli, $query); $col= mysqli_fetch_assoc($result); The code above is what i wrote in the php file — Emerald BAABA amoo, Aug 13 '21 at 23:52

how to access array offset on value of type null

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