PYthon - List of strings into a nested list of strings, where each list contains the elements of each each strings

Question

Basically, I have this:

ls = [
    '###',
    '# a',
    '#b#'
]

and want it to be like:

ls = [
    ['#', '#', '#'], 
    ['#', ' ', 'a'],
    ['#', 'b', '#']
]

Anyone could help me out?

What have you tried already? (Hint, this is string handling 101.) — S3DEV, Aug 12 '21 at 19:44
Does this answer your question? [How can I turn a string into a list in Python?](https://stackoverflow.com/questions/7522533/how-can-i-turn-a-string-into-a-list-in-python) — Jab, Aug 12 '21 at 19:55

score 0 · Accepted Answer · answered Aug 12 '21 at 19:45

0

Just convert each string to a list in a list comprehension

>>> [list(s) for s in ls]
[['#', '#', '#'], ['#', ' ', 'a'], ['#', 'b', '#']]

answered Aug 12 '21 at 19:45

Cory Kramer

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chatax · Answer 2 · 2021-08-12T21:25:47.530

0

By using a list comprehension you can loop through your list and apply some operation on your list items. By putting these items into the list operator you turn an iterable into a list. Because a string is basically a iterable of characters you can convert it into a list of characters with list.

ls = [
    '###',
    '# a',
    '#b#'
]

[list(x) for x in ls]
>> [['#', '#', '#'], ['#', ' ', 'a'], ['#', 'b', '#']]

edited Aug 12 '21 at 21:25

answered Aug 12 '21 at 19:45

chatax

990
3
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Your answer could be more useful if you also explained what your code does instead of just listing the code. – Kritzefitz Aug 12 '21 at 21:22
Thanks for your comment. I added an explanation – chatax Aug 12 '21 at 21:26

score 0 · Answer 3 · answered Aug 12 '21 at 19:53

0

print(list(map(list, ls)))  # [['#', '#', '#'], ['#', ' ', 'a'], ['#', 'b', '#']]

answered Aug 12 '21 at 19:53

Алексей Р

7,507
2
7
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PYthon - List of strings into a nested list of strings, where each list contains the elements of each each strings

3 Answers3