How to run code inside a loop that's not code

Question

I have created a loop that will generate the code I need, however, it is stored as a string and I am unsure how to make this string into executable code.

I have tried eval() and exec() however it throws up an error.

Here's what I have:

for connum in range(farOut):
checker = (f"check{connum} = result['ask'].iloc[{connum}]")
print(checker)
connum=connum+1

I get the desired output printed (which varies in the number count):

> check0 = result['ask'].iloc[0] 
> check1 = result['ask'].iloc[1]
> check2 = result['ask'].iloc[2]

However, what I need to do is then run this check0, check1, check2... etc as code.

So, I need to get the correct result for checker from the output of check0, check1, check2 and so on.

I know I'm fairly close, just need the missing pieces. I tried eval() but it throws up an error:

eval(checker)

File "<string>", line 1
    check0 = result['ask'].iloc[0]
           ^
SyntaxError: invalid syntax

exec(checker) No error - just returns the output above:

> check0 = result['ask'].iloc[0] 
> check1 = result['ask'].iloc[1]
> check2 = result['ask'].iloc[2]

You have an IndentationError. Beside that: there should **never** be any reason to create strings of code to eval or exec them — Patrick Artner, Aug 15 '21 at 11:17
`results = [result['ask'].iloc[whatever] for whatever in range(farOut)]` - result[0] == check0 etc. — Patrick Artner, Aug 15 '21 at 11:18
Whenever you feel the urge to create a sequence of numbered variables, stop and use a list or dictionary! — Klaus D., Aug 15 '21 at 11:22
Thanks for all the feedback. Created a new list now checkerlist = [] and that's going to help me work further through this. I appreciate best practices tips here. — MaximumPain, Aug 15 '21 at 11:28
@PatrickArtner thanks - this worked for me. results = [result['ask'].iloc[i] for i in range(farOut)] print(num, results) — MaximumPain, Aug 15 '21 at 13:23

How to run code inside a loop that's not code

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