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I need to convert hex value for 0xc437 To binary like 1100010000110111 and this binary associated with True false For example here ['True','True','False','False' ,'False' and so on And if the value 0x0000, I want to show all False

Ahmad Attar
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  • Does this answer your question? [Convert hex to binary](https://stackoverflow.com/q/1425493/6045800) and [python: convert a list of 1/0s to a list of boolean](https://stackoverflow.com/q/42010942/6045800) – Tomerikoo Aug 16 '21 at 09:05

1 Answers1

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The simplest might be string formatting:

x = 0xc437
[bool(int(c)) for c in f"{x:016b}"]
# [True, True, False, False, False, True, False, False, False, False, True, True, False, True, True, True]

x = 0x0000
[bool(int(c)) for c in f"{x:016b}"]
# [False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False]

f"{x:016b}" gets you the binary representation of x padded with leading zeroes to length 16.

user2390182
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