Rounding a Whole no. to nearest number in python

Question

Rounding a Whole no. to nearest number in python

Hello!
I am designing a project in python where I'm stuck at a point. I hope I'll get my solution.
Python : 3.7.9 on windows 10
i.e. for example:

1. 0 --> 0
2. 1 --> 0
3. 2 --> 0
4. 3 --> 0
5. 4 --> 0
6. 5 --> 0
7. 6 --> 10
8. 7 --> 10
9. 8 --> 10
10. 9 --> 10
11. 10 --> 10
12. 715306 --> 715310
13. 715305 --> 715300 similarly for all big no.s too Thank you!

Answer 1

I cannot comment because I don't have sufficient reputation. But you can refere to this link here:

Round to 5 (or other number) in Python

A slight tweak can lead you to the right way:

def myround(x, base=10):
    return base * round(x/base)
print(myround(1))

Answer 2

You can use the round() function like this.

print(round(46,-1))
print(round(45,-1))
print(round(715306,-1))

50
40
715310

Answer 3

Round numerical values up and down in Python

When we round values, we go from a numerical value with decimal places to a whole number. With this process we do lose some precision, but the rounded value is often much easier to read and interpret.

Python has three ways to turn a floating-point value into a whole (integer) number:

• The built-in round() function rounds values up and down.

  round(5.4598)

• The math.floor() function rounds down to the next full integer.

  import math

  math.floor(12.75)