How to declare an array of functions?

Question

Suppose I want to declare an array of functions, and try the following

int (*funcs)(int, int)[10];

But turns out that the following declaration stands for an function returning an array, which does not compile.

How can I declare an array of functions properly?

try this: http://www.cplusplus.com/forum/beginner/4639/ I've tried its working — Muhammed Aydogan, Aug 17 '21 at 08:50

score 3 · Accepted Answer · answered Aug 17 '21 at 08:44

3

Strictly speaking you may not declare an array of functions. You may declare an array of function pointers.

It seems you mean

int (*funcs[10])(int, int);

Another way is to introduce a using declaration (or a typedef declaration) like for example

using FP = int( * )( int, int );

FP funcs[10];

or

using FUNC = int ( int, int );

FUNC * funcs[10];

answered Aug 17 '21 at 08:44

Vlad from Moscow

The third option seems a little bit weird. – Karen Baghdasaryan Aug 17 '21 at 09:02
@KarenBaghdasaryan It has its own advantages because the same name FUNC you can using to declare a function and a function pointer.. – Vlad from Moscow Aug 17 '21 at 09:07

score 1 · Answer 2 · answered Aug 17 '21 at 08:45

1

It should be

int (*funcs[10])(int, int);

Or ask help of using (or typedef).

using fp = int (*) (int, int);
fp funcs[10];

answered Aug 17 '21 at 08:45

songyuanyao

2 Answers2