Updating values in dictionary and using enumerate function and print function giving different functions for the below code

Question

x = {'s': 1, 'd': 2, 'f': 4}
x['s'] = 6
print(x)
for q, w in enumerate(x):
    print(q, w)

The above code is giving different outputs when printing it directly and when using enumerate and printing it.

{'s': 6, 'd': 2, 'f': 4}

0 s   
1 d   
2 f

not sure what is your question but keep in mind that enumerate function returns a tuple where the first value is an index 0 based and the second argument since it is a dictionary it iterate over the keys — Orenico, Aug 22 '21 at 10:39

score 1 · Accepted Answer · answered Aug 22 '21 at 10:39

1

You have to iterate through it with dict.items, enumerate just gives the index.

So try this:

for q, w in x.items():
    print(q, w)

answered Aug 22 '21 at 10:39

U13-Forward

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score 0 · Answer 2 · answered Aug 22 '21 at 10:41

As U12-Forward was saying you were printing indices and not the values. You could also print the value as in the code down below. But as he says, if you want to iterate over keys and values you should use items()

x = {'s': 1, 'd': 2, 'f': 4}
x['s'] = 6
print(x)
for q, w in enumerate(x):
    print(q, w, x[w])
>>
0 s 6   
1 d 2  
2 f 4

Updating values in dictionary and using enumerate function and print function giving different functions for the below code

2 Answers2