Working with Hashes that have a default value

Question

Am learning to code with ruby. I am learning about hashes and i dont understand this code: count = Hash.new(0). It says that the 0 is a default value, but when i run it on irb it gives me an empty hash {}. If 0 is a default value why can't i see something like count ={0=>0}. Or is the zero an accumulator but doesn't go to the keys or values? Thanks

Answer 1

0 will be the fallback if you try to access a key in the hash that doesn't exist

For example:

count = Hash.new -> count['key'] => nil

vs

count = Hash.new(0) -> count['key'] => 0

Answer 2

To expand on the answer from @jeremy-ramos and comment from @mu-is-too-short.

There are two common gotcha's with defaulting hash values in this way.

1. Accidentally shared references.

Ruby uses the exact same object in memory that you pass in as the default value for every missed key.

For an immutable object (like 0), there is no problem. However you might want to write code like:

hash = Hash.new([])
hash[key] << value

or

hash = Hash.new({})
hash[key][second_key] = value

This will not do what you'd expect. Instead of hash[unknown_key] returning a new, empty array or hash it will return the exact same array/hash object for every key.

so doing:

hash = Hash.new([])
hash[key1] << value1
hash[key2] << value2

results in a hash where key1 and key2 both point to the same array object containing [value1, value2]

See related question here

Solution

To solve this you can create a hash with a default block argument instead (which is called whenever a missing key is accessed and lets you assign a value to the missed key)

hash = Hash.new{|h, key| h[key] = [] }

2. Assignment of missed keys with default values

When you access a missing key that returns the default value, you might expect that the hash will now contain that key with the value returned. It does not. Ruby does not modify the hash, it simply returns the default value. So, for example:

hash = Hash.new(0) #$> {} 
hash.keys.empty? #$> true
hash[:foo] #$> 0
hash[:foo] == 0 #$> true
hash #$> {}
hash.keys.empty? #$> true

Solution

This confusion is also addressed using the block approach, where they keys value can be explicitly set.

Answer 3

The Hash.new docs are not very clear on this. I hope that the example below clarifies the difference and one of the frequent uses of Hash.new(0).

The first chunk of code uses Hash.new(0). The hash has a default value of 0, and when new keys are encountered, their value is 0. This method can be used to count the characters in the array.

The second chunk of code fails, because the default value for the key (when not assigned) is nil. This value cannot be used in addition (when counting), and generates an error.

count = Hash.new(0)

puts "count=#{count}"
# count={}

%w[a b b c c c].each do |char|
  count[char] += 1
end

puts "count=#{count}"
# count={"a"=>1, "b"=>2, "c"=>3}


count = Hash.new

puts "count=#{count}"

%w[a b b c c c].each do |char|
  count[char] += 1
  # Fails: in `block in <main>': undefined method `+' for nil:NilClass (NoMethodError)
end

puts "count=#{count}"

SEE ALSO:

What's the difference between "Hash.new(0)" and "{}"

Answer 4

TL;DR When you initialize hash using Hash.new you can setup default value or default proc (the value that would be returned if given key does not exist)

Regarding the question to understand this magic firstly you need to know that Ruby hashes have default values. To access default value you can use Hash#default method

This default value by default :) is nil

hash = {}

hash.default # => nil

hash[:key] # => nil

You can set default value with Hash#default=

hash = {}

hash.default = :some_value

hash[:key] # => :some_value

Very important note: it is dangerous to use mutable object as default because of side effect like this:

hash = {}
hash.default = []

hash[:key] # => []

hash[:other_key] << :some_item # will mutate default value

hash[:key] # => [:some_value]
hash.default # => [:some_value]

hash # => {}

To avoid this you can use Hash#default_proc and Hash#default_proc= methods

hash = {}

hash.default_proc # => nil

hash.default_proc = proc { [] }

hash[:key] # => []

hash[:other_key] << :some_item # will not mutate default value
hash[:other_key] # => [] # because there is no this key

hash[:other_key] = [:symbol]
hash[:other_key] << :some_item
hash[:other_key] # => [:symbol, :some_item]

hash[:key] # => [] # still empty array as default

Setting default cancels default_proc and vice versa

hash = {}

hash.default = :default

hash.default_proc = proc { :default_proc }

hash[:key] # => :default_proc

hash.default = :default

hash[:key] # => :default

hash.default_proc # => nil

Going back to Hash.new

When you pass argument to this method, you initialize default value

hash = Hash.new(0)

hash.default # => 0
hash.default_proc # => nil

When you pass block to this method, you initialize default proc

hash = Hash.new { 0 }

hash.default # => nil
hash[:key] # => 0