How do I only print the integers after a decimal point in C

Question

This is my output now

cost = 12.88;
printf("Cost: %.0lf dollars and %.2lf cents", cost, cost-floor(cost));

//output

12 dollars and 0.88 cents

I need my output to look something like this

cost = 12.88
printf("%d Dollars and %d cents", cost)

output

12 dollars and 88 cents

Multiply `cost-floor(cost)` by `100`. You should also round it because floating point is approximate. — Barmar, Sep 03 '21 at 22:17
Does this answer your question? [Extract fractional part of double \*efficiently\* in C](https://stackoverflow.com/questions/5589383/extract-fractional-part-of-double-efficiently-in-c) — Nevus, Sep 04 '21 at 08:42

score 0 · Answer 1 · answered Sep 04 '21 at 05:42

#include <stdlib.h>
#include <stdio.h>
#include <math.h>

void print_cost(double cost)
{
    double int_part;
    double fract_part = modf(cost, &int_part);
    printf(
        "%d Dollars and %d cents", //"%d" based on your example
        (int) int_part, //we must therefore cast to integer
        abs((int)(fract_part * 100.0)) //fract is signed, abs value needed
    );
}

int main()
{
    print_cost(12.88);
    print_cost(-12.88);
    print_cost(12.8899);
    return 0;
}

Reference:

abs
modf

How do I only print the integers after a decimal point in C

1 Answers1