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#include <iostream>

using namespace std;

int main(){

int marks;

float percentage;

cout<<"Marks of Robert are as follows :-"<<endl;

cout<<"78,45,62";

marks=78+45+62;

percentage(marks/300)*100;

cout<<"marks of Robert : "<<marks<<endl;

cout<<"Percentage scored by Robert : "<<percentage<<endl;

return 0;
}
Nathan Pierson
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Rohit Singh
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    Looks like the same problem as [this stab](https://stackoverflow.com/questions/69057703/i-am-trying-to-build-an-program-which-calculates-your-percentage-and-its-giving) at the question. `marks` is an integer. `marks/300` is still an integer, it doesn't get converted to a `float` until after the division has been computed. – Nathan Pierson Sep 07 '21 at 04:44
  • No it is not. Use a debugger. Int 185/Int 300 is zero. You should use float pointing arithmetic in this case. Try to change marks or 300 to float and you will see your result. – honzakuzel1989 Sep 07 '21 at 04:45
  • `percentage = (marks/300)*100;` – Wang Liang Sep 07 '21 at 04:47
  • yeah it worked i've converted the 'marks' to float. – Rohit Singh Sep 07 '21 at 04:54
  • Thnx everybody.. ^_^ – Rohit Singh Sep 07 '21 at 04:56
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    What is the max marks? 300? If so, `percentage = marks*100.f/300;` may give a better result. – Ted Lyngmo Sep 07 '21 at 04:56

1 Answers1

1

the problem is that int cannot have decimals.

so this will solve your problem:

percentage = static_cast<float >(marks) / 300 * 100;

explanation: casting one of the integers to float will cause the compiler to implicitly convert others to float. so the final result will contain decimals

Ted Lyngmo
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Mohammad Mostafa Dastjerdi
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