How to exit a webview (android)?

Question

What I am trying to do is that when user click a button in a webview page, it starts a service and exit the webview(in animation way if possible).

No new activity is started, only the current webview disappear — user822211, Aug 02 '11 at 07:22
finish(); works. It'd be perfect if finish could do something like animation, right! — user822211, Aug 02 '11 at 07:48
Check [this post](http://stackoverflow.com/questions/4330675/how-can-i-add-an-animation-to-the-activity-finish/4330695#4330695) for animation — THelper, Aug 02 '11 at 08:02

score 2 · Answer 1 · edited May 23 '17 at 11:50

2

If you have only 1 activity you can simply start the service and then call finish() on the activity. However, if you have multiple activities you have to make sure that you close them all (see also this post).

edited May 23 '17 at 11:50

Community

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answered Aug 02 '11 at 07:45

THelper

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score 0 · Answer 2 · answered Jul 26 '20 at 08:41

You can exit the webView when a specific link is reached. I believe this solution will work in this case.

 WebViewClient webViewClient = new WebViewClient() {

        @Override
        public void onPageFinished(WebView view, String url) {
            super.onPageFinished(view, url);
            Log.e("PAGE_URL", url);
            if(url.equals("your link...")){
                finish();

            }
        }
    };

How to exit a webview (android)?

2 Answers2