How to get ordinal Numbers in flutter

Question

I tried getting some help from stack and l can across this Python code

I would like to know how to convert this into dart and use it to get ordinal numbers

ordinal = lambda n: "%d%s" % (n,"tsnrhtdd"[(n//10%10!=1)*(n%10<4)*n%10::4])

Jahidul Islam · Answer 1 · 2021-09-08T08:42:16.260

13

Try with this

void main() {
   for(int i =1; i<=100;i++){
     print("$i${ordinal(i)}");
   }
}
String ordinal(int number) {
    if(!(number >= 1 && number <= 100)) {//here you change the range
      throw Exception('Invalid number');
    }

    if(number >= 11 && number <= 13) {
      return 'th';
    }

    switch(number % 10) {
      case 1: return 'st';
      case 2: return 'nd';
      case 3: return 'rd';
      default: return 'th';
    }
}

output: 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th ..................

edited Sep 08 '21 at 08:42

answered Sep 08 '21 at 08:13

Jahidul Islam

11,435
3
17
38

Thank you for response it uses day of the month?.. is there a way to extend it. For example 111th or more. – oceanmanta Sep 08 '21 at 08:16
you can change the value range in ordinal number ` if(!(number >= 1 && number <= 100)) ` – Jahidul Islam Sep 08 '21 at 08:19
Do you even need the range check? It should work regardless, right? – Stack Underflow Dec 07 '21 at 21:36
yes, you are right – Jahidul Islam Dec 08 '21 at 04:52

score 1 · Answer 2 · answered Sep 08 '21 at 09:33

Resuable version of accepted answer.

main() {
  print(toOrdinal(3)); 
  // -> 3rd
  print(ordinalGenerator(end: 1000));
  // -> [1st, 2nd, 3rd, 4th,..., 1000th]
  print(ordinalGenerator(start: 7, end: 14));
  // -> [7th, 8th, 9th, 10th, 11st, 12nd, 13rd, 14th]
}

List ordinalGenerator({int start = 1,required int end}) {
  if (start < 1) throw Exception('Start Number Can\' be less than 1');
  if (start > end) throw Exception('Invalid Range');

  return List.generate(
    end - (start == 1 ? 0 : start - 1),
    (index) => toOrdinal(index + start),
  );
}

String toOrdinal(int number) {
  if (number < 0) throw Exception('Invalid Number');

  switch (number % 10) {
    case 1:
      return '${number}st';
    case 2:
      return '${number}nd';
    case 3:
      return '${number}rd';
    default:
      return '${number}th';
  }
}

Damilola Boiyelove · Answer 3 · 2022-09-22T21:16:37.260

Using extensions, the code below can be used with any int type. Since ordinals are based on the last figure of a digit; this int extension takes the integer value and converts it to string Next, it gets the last index of said string and uses that to determine the ordinal.

extension NumberParsing on int {
  String toOrdinalString() {
    if ((this < 0)) {
      //here you change the range
      throw Exception('Invalid number: Number must be a positive number');
    }
    if (this == 0) {
      return '0';
    }

    String stringValue = toString();

    switch (stringValue[stringValue.length - 1]) {
      case '1':
        return stringValue + 'st';
      case '2':
        return stringValue + 'nd';
      case '3':
        return stringValue + 'rd';
      default:
        return stringValue + 'th';
    }
  }
}

// Usage:
int someIntValue = 25;
someIntValue.toOrdinalString();

//Output:
25th

// Generate Ordinals from 1 to 100
for(int i =1; i<=100;i++){
     print(i.toOrdinalString());
   }

ZsomborRajki · Accepted Answer · 2023-03-14T20:19:32.320

0

I made a package for this using the native platform libraries.

https://pub.dev/packages/ordinal_formatter

final ordinalString = await OrdinalFormatter().format(2) ?? ''; 
// -> 2nd

final localisedOrdinalString = await OrdinalFormatter().format(2, 'en_US') ?? ''; 
// -> 2nd

edited Mar 14 '23 at 20:19

answered Mar 12 '23 at 18:38

ZsomborRajki

16
2

How to get ordinal Numbers in flutter

4 Answers4