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if x,y,z are all 1 its giving the answer 111 rather than 3

    x=prompt ("Enter first Number"); 
y=prompt ("Enter second Number");
z=prompt ("Enter third Number"); 
p= x + y + z ;
why_tf_you_do_tis
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1 Answers1

0

You could use something like this

x = parseInt(prompt("Enter first Number"), 10);
y = parseInt(prompt("Enter second Number"), 10);
z = parseInt(prompt("Enter third Number"), 10);
p = x + y + z;
console.log(p)
Dibash Sapkota
  • 617
  • 5
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  • Please use `parseInt` [_with_ the second parameter, `10`](/q/16880327/4642212). Consider using [`Number`](//developer.mozilla.org/docs/Web/JavaScript/Reference/Global_Objects/Number#Function_syntax) or [`parseFloat`](//developer.mozilla.org/docs/Web/JavaScript/Reference/Global_Objects/parseFloat) instead. – Sebastian Simon Sep 11 '21 at 04:33