Post multiple images with FastAPI and Python requests

Question

I want to know how to use requests when use two image files as inputs.

server

from fastapi import FastAPI, File

app = FastAPI()

@app.post("/images")
def images(img1: bytes = File(...), img2: bytes = File(...)):
    # **do something**
    return {"message": "OK"}

I succeded to post with curl command like below,

curl -X POST \
  'http://127.0.0.1:8000/images' \
  -H 'accept: application/json' \
  -H 'Content-Type: multipart/form-data' \
  -F 'img1=@<IMG1_FILE>;type=image/<EXTENSION>' \
  -F 'img2=@<IMG2_FILE>;type=image/<EXTENSION>'

but I failed with scripts using requests like below, and got 400 BAD Request

import requests

url = "http://127.0.0.1:8000/images"
headers = {"accept": "application/json", "content-type": "multipart/form-data"}
files = {"img1": open("img1_path.jpg", "rb"), "img2": open("img2_path.jpg", "rb")}

response = requests.post(url, headres=headers, files=files)

can anyone help me??

`headeres=headers` - did you mean `headers=headers`? – MatsLindh Sep 15 '21 at 09:12 — MatsLindh, Sep 15 '21 at 09:12
sorry this is typo, yes `headers=headers` – ktro2828 Sep 15 '21 at 09:49 — ktro2828, Sep 15 '21 at 09:49
but the fixing typo doesn't matter whether fix this problem – ktro2828 Sep 15 '21 at 10:11 — ktro2828, Sep 15 '21 at 10:11

score 0 · Answer 1 · answered Sep 15 '21 at 10:46

Firstly ensure you installed python-multipart package.

Then Remove the content-type from request headers like below:

import requests

url = "http://127.0.0.1:8000/images"
headers = {"accept": "application/json"}
files = {"img1": open("img1_path.jpg", "rb"), "img2": open("img2_path.jpg", "rb")}

response = requests.post(url, headers=heaers, files=files)

Post multiple images with FastAPI and Python requests

1 Answers1