device vibration keeps repeating infinitely

Question

im trying to vibrate device and repeat this pattern for 3 times so in total 6x vibrations. Im using code bellow but my device keeps vibrating infinitely. How to stop vibrating after those 3 repeats?

private void deviceVibration (){
   
   long[] pattern = {0, 2000, 1000, 2000,1000};
   vibrator.vibrate(pattern,3);

}

you have the answer below which is perfect but if you want to see breifly https://stackoverflow.com/a/23566943/11647620 — Usama Altaf, Sep 17 '21 at 13:15
http://programondaspot.blogspot.com/2015/06/simple-android-vibration-application.html — Usama Altaf, Sep 17 '21 at 13:18

Skizo-ozᴉʞS ツ · Accepted Answer · 2021-09-17T13:19:28.377

2

According to the Vibrator Documentation

public void vibrate (long[] pattern, int repeat)

This long[] pattern is an array of longs of times for which to turn the vibrator on or off. This int repeat is the index into pattern at which to repeat, or -1 if you don't want to repeat.

So if you put the 3 it will repeat the 3 index position of your pattern.

long[] pattern = {0, 2000, 1000, 2000,1000}; <-- 2000 will be repeated

So the pattern is ok, you need to remove one to just vibrate three times and then just change your 3 for -1 to don't repeat.

edited Sep 17 '21 at 13:19

answered Sep 17 '21 at 13:03

Skizo-ozᴉʞS ツ

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so if i change index 0 in pattern to 3 `long[] pattern = {3, 2000, 1000, 2000,1000};` and set `vibrator.vibrate(pattern,0);` it should repeat only 3 times right? – zon1k Sep 17 '21 at 13:29

score 0 · Answer 2 · answered Sep 17 '21 at 13:31

0

you can try this

long[] pattern = {0, 2000, 1000, 2000,1000};
 vibrator.vibrate(pattern, -1);

-1 for to vibrate only as mentioned in the pattern.

answered Sep 17 '21 at 13:31

CodeWithVikas

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it will vibrate 2 times i want to repeat this pattern 3 times – zon1k Sep 17 '21 at 13:34
@zon1k then use `long[] pattern = {0, 2000, 1000, 2000,1000, 2000,1000};` – Usama Altaf Sep 17 '21 at 13:35

score 0 · Answer 3 · answered Sep 17 '21 at 13:38

0

Your code should like this

long[] pattern = {0, 2000, 1000, 2000,1000, 2000,1000};
vibrator.vibrate(pattern, -1);

As Skizo-ozᴉʞS said accept his answer it is more perfect

answered Sep 17 '21 at 13:38

Usama Altaf

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device vibration keeps repeating infinitely

3 Answers3