Python fill array with 0's without numpy

Question

I know in python you can fill an array with 0's using numpy.zeroes(size) but as part of learning I am asked to not use numpy, so my question is, is there a way to fill an array without numpy.zeroes function?

specificly How do I fill the following list with 0's in the following functions?

def myHistWithRescale(listOfNums, maxInt):
    """Givne a list of real numbers in any range, first scale the numbers to
    inters between 0 and maxInt (inclusive), then return the number of occurrences
    of each integer in a list
    """
    rescaledData = rescaleToInt(listOfNums, maxInt)  
    return counts

The title doesn't seem to match the comment in the method. – Unmitigated Sep 18 '21 at 01:25 — Unmitigated, Sep 18 '21 at 01:25
How is that function relevant to the question? – wjandrea Sep 18 '21 at 01:26 — wjandrea, Sep 18 '21 at 01:26

score 2 · Answer 1 · answered Sep 18 '21 at 01:26

2

To create a list of size n of all zeros, just write [0] * n

answered Sep 18 '21 at 01:26

Frank Yellin

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score 1 · Accepted Answer · answered Sep 18 '21 at 01:37

1

For the function, you can do: arr = [0] * maxInt. Where maxInt is the size of list.
Similarly if you want to fill an array with something other than 0; you can just replace the 0 with any number you want to fill

answered Sep 18 '21 at 01:37

kevin

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Python fill array with 0's without numpy

2 Answers2