how c++ handles the arithmetic between an int and an unsigned int?

Asked Sep 19 '21 at 17:34

Active Sep 19 '21 at 17:34

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I am a beginner in cpp, reading about the topic Type-conversions. I want to ask how cpp handles the arithmetic between an int and an unsigned int inernally to calculate the result?

For example, something like:

long int result = a-variable-in-int + a-variable-in-unsigned-int

I am interested in knowing the basic concept that goes inside the cpp compiler for running this expression. If someone can explain this in simple terms, that would be helpful...

asked Sep 19 '21 at 17:34

Aadil Hoda

1

This question has been asked before, check this: https://stackoverflow.com/questions/25609091/what-happens-when-i-mix-signed-and-unsigned-types – Pepijn Kramer Sep 19 '21 at 17:37
@PKramer my bad, thanks for pointing it out – Aadil Hoda Sep 19 '21 at 17:38

how c++ handles the arithmetic between an int and an unsigned int?

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