"Days between" should return 1 when going over a day boundary, even within 24 hours

Question

I have the current function:

function getDaysBetween($start, $end) {
    $start = strtotime($start);
    $end = strtotime($end);
    $dateDiff = abs($end- $start);
    $daysBetween = floor($dateDiff/(60*60*24));
    return $daysBetween;
}

The function above does return the days between.

So, for example, August 3 at 3.00 AM minus August 2 at 11PM gives 0.

In this case I would like it to return 1, since these are different days. How can I achieve that?

see http://stackoverflow.com/questions/3371011/how-to-subtract-two-dates-and-times-to-get-difference — PtPazuzu, Aug 03 '11 at 11:13

score 2 · Accepted Answer · answered Aug 03 '11 at 11:14

2

Instead of

$start = strtotime($start);
$end = strtotime($end);

use

$start = strtotime('00:00:00', strtotime($start));
$end = strtotime('00:00:00', strtotime($end));

answered Aug 03 '11 at 11:14

binaryLV

9,002
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score 1 · Answer 2 · answered Aug 03 '11 at 11:12

1

Remove the time from your $start and $end, simply pass the date. e.g. 03/08/2011 instead of 03/08/2011:03:00:00

answered Aug 03 '11 at 11:12

Calum

5,308
1
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score 0 · Answer 3 · answered Aug 03 '11 at 11:15

function getDaysBetween($start, $end) {
    $start = new DateTime($start);
    $end = new DateTime($end);
    $start->setTime(0,0,0);
    $end->setTime(0,0,0);
    $dateDiff = abs($end->getTimestamp() - $start->getTimestamp());
    $daysBetween = floor($dateDiff/(60*60*24));
    return $daysBetween;
}

"Days between" should return 1 when going over a day boundary, even within 24 hours

3 Answers3