find and create a new array just with one sort of value and eliminate duplicates (if many)

Question

I'm trying to find a method for sorting an array by uuid and eliminate the duplicate.

For exemple i have a array like this :

const x = [
{id: 1, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 2, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 3, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 4, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 5, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 6, uuid: xxxx-xxxx-xxxx-xxxx, content: 'string'},
{id: 7, uuid: yyyy-yyyy-yyyy-yyyy, content: 'string'},
{id: 8, uuid: zzzz-zzzz-zzzz-zzzz, content: 'string'}
]

And i'm trying to find a simple way for making this in result :

const x = [xxxx-xxxx-xxxx-xxxx, yyyy-yyyy-yyyy-yyyy, zzzz-zzzz-zzzz-zzzz]

I know it's maybe basic but my brain is off i guest ...

Thanks !

What does this have to do with _sorting_? You apparently want a completely different structure as result, which means this is _not_ sorting. — CBroe, Sep 20 '21 at 14:42
that will not return X times the uuid with xxxx-xxxxx-xxxx-xxxx value ? — Ludovic Argenty, Sep 20 '21 at 14:45
combined with @CBroe recommended duplicate: https://stackoverflow.com/questions/1960473/get-all-unique-values-in-a-javascript-array-remove-duplicates — pilchard, Sep 20 '21 at 14:47

score 2 · Accepted Answer · edited Sep 20 '21 at 21:45

2

Try this, but i used a string type for uuid:

[...new Set(x.map(e => e.uuid))].sort()

edited Sep 20 '21 at 21:45

DecPK

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answered Sep 20 '21 at 14:48

D4NT3

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This solution won't work if the order of `xxxx...` and `yyyy...`changes. OP has asked `sorting an array by uuid` – DecPK Sep 20 '21 at 15:04
You would have to use a sort() afterwards, I'll edit it asap, using phone currenly – D4NT3 Sep 20 '21 at 21:45
1

I've edited the solution and It will work as expected – DecPK Sep 20 '21 at 21:45

find and create a new array just with one sort of value and eliminate duplicates (if many)

1 Answers1