How to parse JSONP with PHP

Question

Possible Duplicate:
Extract JSONP Resultset in PHP

I get the response in the following format. Im facing trouble on how to get inside "Plugin" variable and access other variables inside it.I used json_decode(), but i cant access the variables.

Plugin
(
{ 

"plugin_a":"abc", 
"plugin_b":"abc", 
"plugin_c":"abc" 
}
)

I tried

$a = json_decode($json,true);
echo  $a['plugin_a'];

I dont get any output.

echo var_dump($json); gives me

string 'Plugin({
  "plugin_a":"abc",
  "plugin_b":"abc",
  "plugin_ce":"abc" })'

Thanks everyone for quick response...this code solved by problem http://codepad.org/eJXeaXIO — simplyblue, Aug 03 '11 at 14:55

score 0 · Answer 1 · answered Aug 03 '11 at 14:17

0

try substr();

http://sandbox.phpcode.eu/g/40c20.php

<?php
$json = substr('Plugin
(
{ 

"plugin_a":"abc", 
"plugin_b":"abc", 
"plugin_c":"abc" 
}
)', 9, -1);

print_r(json_decode($json));

answered Aug 03 '11 at 14:17

genesis

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3

a more general approach would be to preg_match everything between the the first opening ( and last closing ). – Gordon Aug 03 '11 at 14:24
Thanks...this code solved my problem. http://codepad.org/eJXeaXIO – simplyblue Aug 03 '11 at 14:55

score 0 · Answer 2 · answered Aug 03 '11 at 14:36

Perhaps this will work for you:

$data=array('plugin_a'=>'abc','plugin_b'=>'bcd','plugin_c'=>'cde');
$json='{"Plugin":'.json_encode($data).'}';
$a=json_decode($json,true);
echo $a['Plugin']['plugin_a'];

It appears as though the actual json array may not have integrity. If this solution doesn't fit, can you post the code that actually builds the json array?

How to parse JSONP with PHP

2 Answers2