How can I sort scores in a leaderboard?

Question

I've been trying to sort a top-5 leaderboard which includes the score and the username of the account that got the score. Here is my current code:

g = open("scores.txt", "r")
score1 = g.readline().strip()
score2 = g.readline().strip()
score3 = g.readline().strip()
score4 = g.readline().strip()
score5 = g.readline().strip()
print(score1,score2,score3,score4,score5)
print(sorted([score1,score2,score3,score4,score5], reverse = True))
g.close()

It seems to work, but it only sorts the leftmost digits of the scores, for example it sorts 100coolguy 50otherguy 10coolguy 2000coolguy 2otherguy as 50otherguy 2otherguy 2000coolguy 10coolguy 100coolguy.

A list of the scores, and how they should be formatted afterwards:

100otherexample 50example 10otherexample 2000example 2example
2000example 100otherexample 50example 10otherexample 2example

Hi and welcome to StackOverflow! Can you include the minimal code and dependencies to reproduce the problem? In this case, that would be a list of the names and scores (without the IO) and how they should be formatted afterwards. — erip, Sep 22 '21 at 11:11
share `"scores.txt"` and the expected result. Share the code that write to the file as well. — balderman, Sep 22 '21 at 11:15
Does this answer your question? [How to correctly sort a string with a number inside?](https://stackoverflow.com/questions/5967500/how-to-correctly-sort-a-string-with-a-number-inside) — Stef, Sep 22 '21 at 13:38

score 1 · Answer 1 · answered Sep 22 '21 at 11:14

1

from natsort import natsorted
print(natsorted([score1,score2,score3,score4,score5], reverse = True))

answered Sep 22 '21 at 11:14

Eumel

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score 1 · Accepted Answer · answered Sep 22 '21 at 11:15

1

You can first find digits then sort base digits like below:

st = ['100coolguy' , '50otherguy' , '10coolguy' , '2000coolguy' ,'2otherguy']

def find_int(text):
    return int(''.join(t for t in text if t.isdigit()))


st.sort(key=find_int, reverse=True)
print(st)

Output:

['2000coolguy', '100coolguy', '50otherguy', '10coolguy', '2otherguy']

answered Sep 22 '21 at 11:15

I'mahdi

23,382
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This would given wrong results if there are other digits later in the strings; for instance `'50coolguy12'` would be sorted as if they had a score of 5012. Instead, you can use `itertools.takewhile`: `int(''.join(itertools.takewhile(str.isdigit, text)))` – Stef Sep 22 '21 at 13:29

Tzane · Answer 3 · 2021-09-22T11:28:22.410

You need give a custom key to sorted key is what is evaluated instead of the whole list item in the sorting process:

A regex implementation:

import re

l = ["100coolguy", "50otherguy", "10coolguy", "2000coolguy", "2otherguy"]

def my_key(item):
    item_split = re.split("[a-z]", item, 1, flags=re.I)
    return int(item_split[0])

l_sorted = [sorted(l, key=my_key, reverse=True)]
print(l_sorted)

Splits at any character ("[a-z]") for 1 time and ignores case with re.I.

https://docs.python.org/3/howto/sorting.html#key-functions

How can I sort scores in a leaderboard?

3 Answers3