How can i print 'n' numbers in consecutive order in python?

Question

I need your help Senpai!

How can I print 'n' number of series in a consecutive order?

Basically, I want to print 'n' numbers in series without spaces.

For example in my code,

    for x in range(1, n+1):
        print(x)

Output for n=5

But i want to get output like: 12345 (without any spaces in a single line).

Help me with this please!

`print(*range(1, n+1), sep="")` – Niel Godfrey Pablo Ponciano Sep 22 '21 at 16:18 — Niel Godfrey Pablo Ponciano, Sep 22 '21 at 16:18

Gábor Pálovics · Accepted Answer · 2021-09-22T16:22:05.393

1

Use:

n = 10
print(*range(1,n+1), sep="")

print(*range(1,n+1)) is equivalent of print(1, 2, ..., n)
And you need sep="" so it print doesn't displayadditional new line characters between the numbers

edited Sep 22 '21 at 16:22

answered Sep 22 '21 at 16:18

Gábor Pálovics

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upvoted, but still an explanation would have been nice – rv.kvetch Sep 22 '21 at 16:19
as mentioned in comments, you might not need `end=''` – rv.kvetch Sep 22 '21 at 16:20
1

Edited it accordingly – Gábor Pálovics Sep 22 '21 at 16:22
This worked for me, thanks a lot. – Ghanshyam Singh Shaktawat Sep 22 '21 at 16:22

How can i print 'n' numbers in consecutive order in python?

1 Answers1