Python datetime.timedelta not working with in arg

Question

I'm trying to do a web scraper with selenium which will run as a AWS lambda function every week to book a time slot for me to go and play some tennis. My booking site is releasing new bookable time slots at midnight 2 weeks ahead of time. I have a lambda function that will run every Wednesday at midnight.

My issue is actually when I'm using datetime.timedelta(days=14) I get a compiler error for the inarg days. screenshot

bookingTime = nowInUtc + timedelta(days=14)

I have seen multiple examples of this syntax:

Python: Adding 3 weeks to any date

Adding days to a date in Python

What am I missing?

Im using Jetbrainz PyCharm Idea Python 3.9.7

my imports

from datetime import datetime, timedelta
import pytz

Please post the entire code sample, and the error message as well. — Alex, Sep 25 '21 at 09:06
Please provide enough code so others can better understand or reproduce the problem. — Community, Oct 03 '21 at 10:51

score 0 · Accepted Answer · answered Sep 25 '21 at 09:31

0

This code works and gets the date two weeks from now. If you want to know why you code doesn't work, you'll have to post your code :)

from datetime import datetime, timedelta

now = datetime.now()
in_two_weeks = now + timedelta(days=14)
print(in_two_weeks)

answered Sep 25 '21 at 09:31

Johan Kuylenstierna

189
5

if you want UTC time, import `timezone` from the datetime module as well and use `datetime.now(timezone.utc)`. – FObersteiner Sep 25 '21 at 10:12
Ok im stupid. Its just the color red in my idea. My code works. I just assumed it was a compiler error. Thanks for the help! – realWallawalla Sep 27 '21 at 13:26

Python datetime.timedelta not working with in arg

1 Answers1