How to set .then to var?

Question

So I am trying using a package called "app-store-scraper"

All of the examples look something like this:

var store = require('app-store-scraper');

store.app({id: 553834731}).then(console.log).catch(console.log);

but all it does is print it to the console. So I was wondering how to put it into a variable?

I have tried to do var test = store.app({id: 553834731}) but it returns nothing

Edit: I'm using this to return like res.end(); on a webserver. so I'm trying to return store.app()

Igor Shmukler · Answer 1 · 2021-09-27T17:27:44.663

0

Your function - store.app() returns a promise.

you can do:

var test = store.app({id: 553834731})
test.then(console.log);

in a modern async/await syntax, which is a lot easier to understand, your code can be rewritten:

try {
  const ret = await store.app({id: 553834731});
  console.log(ret);
}
catch (e) {
  console.log(e);
}

edited Sep 27 '21 at 17:27

answered Sep 27 '21 at 14:38

Igor Shmukler

I'm using this to return like ```res.end();``` on a webserver. and I'm very new to javascript so i dont know how async works. So to clairfy: how do i return the ```store.app()``` – oredgaming Sep 27 '21 at 14:54

score 0 · Answer 2 · answered Sep 27 '21 at 14:54

0

let result;

store.app({ id: 553834731 }).then(res => result = res).catch(console.error);

or

const result = await store.app({ id: 553834731 });

answered Sep 27 '21 at 14:54

SharedRory

2 Answers2