Get a return from a then()

Question

I have this part of code:

client.on("messageCreate", msg => {
    if (msg.content.toLowerCase().startsWith('-p')) {
        msg.content = msg.content.slice(3);
        enlace = google.youtube('v3').search.list({
            key: process.env.YOUTUBE_TOKEN,
            part: 'id',
            q: msg.content,
            maxResults: 1
        }).then((response) => {
            const { data } = response;
            data.items.forEach((item) => {
                const link = item.id.videoId;
                console.log(link)
                console.log(typeof (link))
                return link
            })
        }).catch((err) => console.log(err));
        console.log(enlace)
    }
})

What i pretend it to do, is to get the data from the variable "link" and use it outside the .then(), then i would do something else with that data The problem is that, in the log i get this:

ACA EMPIEZA EL LOG
Poe esta online
Promise { <pending> }
YVkUvmDQ3HY
string

It seems the line console.log(enlace) executes before the other to logs and without the value i expect. How can i get the execution to wait for the data to be already stored in the variable enlace before logging it and how to actually store the value of link into enlace

Is `enlace` supposed to be an array of `link`'s? if so then you should use map instead of forEach and return the array. you would also need to `await` or chain another `then` to wait for the promise to resolve before console.log — Matt Aft, Sep 27 '21 at 18:43
BTW you don't need all this `.catch((err) => console.log(err));`, simply `.catch(console.log)` will do. But you might even want [`console.error`](https://developer.mozilla.org/en-US/docs/Web/API/console/error). — msanford, Sep 27 '21 at 18:43

Get a return from a then()

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