sed does not render parameter value

Asked Sep 28 '21 at 08:01

Active Sep 28 '21 at 08:01

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I have a scenario where i need to generate and update values of secret key at runtime and update my configuration files. The value of fernet key doesn't seem to render and it is getting replaced by string $fernet_key itself. Have tried Within "" {} () . Nothing seems to be working. Please advise.

fernet_key="$(python3 -c 'from cryptography.fernet import Fernet; print(Fernet.generate_key().decode())')"
sed -i -e 's|{FERNET_KEY}|$fernet_key|g' ~/config.yml

I am doing similar for secret key though with echo which is working perfectly though.

secret_key="$(python3 -c 'from base64 import b64encode;import os; print(b64encode(os.urandom(64)).decode())')"
echo -e "SECRET_KEY=$secret_key" > ~/.env

asked Sep 28 '21 at 08:01

14578446

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Use double quotes, `"s|{FERNET_KEY}|$fernet_key|g"`. What is the value of `$fernet_key`? – Wiktor Stribiżew Sep 28 '21 at 08:05
@WiktorStribiżew fernet key is random string. But i have tried with test value like 'abcd' . that did not work too. – 14578446 Sep 28 '21 at 08:10
" seem to have done the magic. Thanks @WiktorStribiżew. "s|{FERNET_KEY}|$fernet_key|g" worked. – 14578446 Sep 28 '21 at 08:13

sed does not render parameter value

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