Why is my if statement ignored even after typing hello in input

Question

#include <stdio.h>

int main()
{
    char a[]=("hello");
    char b[10];
    printf("enter value: ");
    scanf("%s",b);
    if(b==a){
        printf("%s",a);
    }

    return 0;
}

when I run this code it shows me to 'enter value' as expected but when I enter 'hello' which is equal to variable 'a' it is not showing the if statement.

`b==a` is a pointer comparison, you want `strcmp` – UnholySheep Sep 28 '21 at 08:56 — UnholySheep, Sep 28 '21 at 08:56

score 1 · Answer 1 · answered Sep 28 '21 at 08:57

1

== will check that a and b are pointers to the same string in memory, which they aren't. To compare the contents of these strings, you can use strcmp:

if (strcmp(a, b) == 0) {
    printf("%s", a);
}

answered Sep 28 '21 at 08:57

Mureinik

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score 0 · Answer 2 · answered Sep 28 '21 at 08:57

0

If you want scanf to consume one line of input, write scanf("%s\n",b);.

Another point is that you want to compare buffer contents, instead of pointers. Use strcmp function in the if() clause.

answered Sep 28 '21 at 08:57

arrowd

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Why is my if statement ignored even after typing hello in input

2 Answers2