allocation memory in C int p = malloc(n sizeof(int)); vs int p = (int)malloc(3 * sizeof(int));

Question

I am trying to learn what is the difference between:

int *p = malloc(3 * sizeof(int)); AND
int *p = (int*)malloc(3 * sizeof(int));

when initializing a dynamic array in C, and I can't get it, any help?

https://stackoverflow.com/questions/605845/do-i-cast-the-result-of-malloc — William Pursell, Oct 01 '21 at 01:08

score 1 · Answer 1 · answered Oct 01 '21 at 01:07

In C there's no need for such operation, which is called cast, because a void* pointer is implicitly convertible to any kind of pointer.

In C++ you would require it because there's no such implicit conversion, but you will be using new instead that malloc, which wouldn't require it at all.

allocation memory in C int *p = malloc(n * sizeof(int)); vs int *p = (int*)malloc(3 * sizeof(int));

1 Answers1

allocation memory in C int p = malloc(n sizeof(int)); vs int p = (int)malloc(3 * sizeof(int));