Concept behind the execution of this code?

Question

Executing this command is getting me an infinite loop also in the while condition I wrote i=30 instead of i<=30 wanna know what does i=30 does to my code:

#include <iostream>
using namespace std;
int main()
{
  
  int i=30;//initialization
  
  while (i =30)
  {
      cout<< i<< ' '; 
      i=i+1;
  } 
 
    
}

See [Why should I always enable compiler warnings?](https://stackoverflow.com/questions/57842756/why-should-i-always-enable-compiler-warnings) — jarmod, Oct 03 '21 at 19:14
The 11th commandment: **THOUGH SHALT HEED THY WARNINGS!** Or else. — Peter - Reinstate Monica, Oct 03 '21 at 19:16

score 0 · Answer 1 · answered Oct 03 '21 at 19:10

0

while (i = 30) assigns the value 30 to the variable i, and then uses the resulting i as a condition. Since i is non-zero, it is considered true, and the loops runs forever.

As such, the cout will always print 30 and the increment of i will be undone at every iteration.

answered Oct 03 '21 at 19:10

Jeffrey

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also whatever value i assign to while initializing it runs infinite loop of 30 only what can be the reason..? – Tejas Aditya Oct 03 '21 at 21:03
@TejasAditya like Jeffrey said, `while (i = 30)` is assigning 30 to `i`, so it doesn't matter what initial value you set `i` to, it is being overwritten on every iteration. You need to use `==` (equality comparison), not `=` (assignment), eg: `while (i == 30)` – Remy Lebeau Oct 03 '21 at 21:14

Concept behind the execution of this code?

1 Answers1