How to select a word which contains a previous word?

Question

I'm trying to select a word that is on the second line, but first I need to check if there is a word on the first line, regex example:

(?<=isaac)select

this is the text

abcdefgisaachijklmnopqrstuvwxyz
abcdefgselecthijklmno

Just to clarify my idea a little

Why doesn't this regex work when isaac precedes select?

How can I solve this?

Did you try: `(?<=isaac)([\S\s]*)select` this will capture everything between isaac and select. — iPaat, Oct 05 '21 at 00:57
@user3783243 I need to select the word "select" and not select the word "isaac". But to select I need to check if there is the word "isaac" before "select" — megaultron, Oct 05 '21 at 01:14

score 3 · Accepted Answer · answered Oct 05 '21 at 01:43

3

You can change issac so it is in a non-capture group, and allow for anything until select is present.

(?s)(?:isaac.*)(select)

The (?s) modifies the . operator so it allows for new lines as well.

https://regex101.com/r/qPQH25/1

answered Oct 05 '21 at 01:43

user3783243

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Your regex matches `"My name is isaac m. newton, let's see if select is \non the next line"`. Also I don't understand the point of having `isasc.*` in a non-capture group. – Cary Swoveland Oct 05 '21 at 02:33

score 1 · Answer 2 · answered Oct 05 '21 at 02:32

Since the two words are given there is no point to select the word in the second line; it is enough to determine if the first word is in the first line and the second word is in the second line.

The needed regular expression is simple:

.*isaac.*\n.*select

Start your engine!

How to select a word which contains a previous word?

2 Answers2