regex Python: split CamelCase AND STOP IF there is space

Question

All help is greatly appreciated folks I found a brilliant solution here How to do CamelCase split in python ,

re.sub('([A-Z][a-z]+)', r' \1', re.sub('([A-Z]+)', r' \1', string)).split()

However I need it to stop IF THERE is SPACE Example

t = 'YankeesMets' >>> ['Yankees', 'Mets']
tt = 'CubsWhite Sox' >>> ['Cubs', 'White'] (no more words after the first whitespace)

So, how do I change regex to STOP splitting CamelCase if it finds space?

What is the current output for `CubsWhite Sox` and what is the expected output? — Tim Biegeleisen, Oct 09 '21 at 09:59
Current output is ['Cubs', 'White', 'Sox']... I expect it to be ['Cubs', 'White'] — data_runner, Oct 09 '21 at 10:02

score 2 · Accepted Answer · answered Oct 09 '21 at 10:41

You can get the part of the string from its beginning to the first whitespace and apply your solution to that part of the string:

re.sub('([A-Z][a-z]+)', r' \1', re.sub('([A-Z]+)', r' \1', text.split()[0])).split()

See the Python demo, and the following demo below:

import re
l = ['CubsWhite Sox', 'YankeesMets']
for s in l:
    print(f"Processing {s}")
    first = s.split()[0]
    result = re.sub('([A-Z][a-z]+)', r' \1', re.sub('([A-Z]+)', r' \1', first)).split()
    print(result)

Output:

Processing CubsWhite Sox
['Cubs', 'White']
Processing YankeesMets
['Yankees', 'Mets']

regex Python: split CamelCase AND STOP IF there is space

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