I have a y/n query at the end of the game which will restart the game or exit the game.
y and n work as they should, but if I enter any other letter even if it does print the "please try again message", it restarts the game anyway. I thought it should only do that if I put continue, but I haven't
I also want it to recognize y or n as upper case, is there a command in python that allows a letter to be recognized regardless of if its upper or lowercase?
play_again = input('Would you like to play again?(y/n) ')
if play_again == 'y': #loop restarts
print('Starting another game...')
continue
elif play_again == 'n': #loop is exited
print('Thank you for playing! You have now exited the game.')
break
else:
print ("I don't recognize that character, please select y or n")
I have provided the loop as requested, but the last time I did this I got in trouble:
number_of_stones = int(input('Select between 30-50 stones to start your game: ' )) #player1 chooses stones
if number_of_stones >= 30 and number_of_stones <= 50:
print('Starting the game...')
has_winner = False # Winner = False since there no winners (start of game)
while True:
for player in player_list:
if has_winner: # if there is a winner, exit loop
break
# display whose turn is it
print('\n{}\'s turn:'.format(player))
while True:
# if the player is computer use strategy that is mentioned in assignment 2
if player == 'Mr Computer':
remainder = number_of_stones%3
if remainder == 0:
stones_to_remove = 2
else:
stones_to_remove = 1
# if the player is not the computer
else:
stones_to_remove = int(input('Select between 1-3 stones to remove: '))
# assess the number of stones remaining and print the remainder to the screen
if stones_to_remove >= 1 and stones_to_remove <= 3:
number_of_stones -= stones_to_remove
print('Number of stones remaining:',number_of_stones)
if number_of_stones <= 0:
print('The winner is:',player,"!")
has_winner = True
break
else: # show error and let the user input again
print("I'm sorry, that number is outside the range. Please choose a number between 1 and 3")
if has_winner == True: # if the winner=true then exit loop
break
play_again = input('Would you like to play again?(y/n) ').lower() #only accepts lower case letter
if play_again == 'y': #loop restarts
os.system('cls') # clear the console
print('Starting another game...')
continue
elif play_again == 'n': #loop is exited
print('Thank you for playing! You have now exited the game.')
break
else:
print("I'm sorry, that number is outside the range. Please select between 30 and 50 stones.")
