Joining two lists in this order

Question

list1 = [2 3 4]
list2 = [0 1 2 3]

desired output / or similar

(2,0) (2,1) (2,2) (2,3) (3,0) (3,1) (3,2) (3,3) (4,0)

i.e. for every val in list1, iterate through list2 before moving to next val in list1

I might be here for the next day trying to do it :/ ... tyty

What have you tried so far? The approach you are describing seems to be in the right direction... — Mortz, Oct 12 '21 at 10:42
So nested for loop would be a great solution, like mentioned in the comments by Pingu and timgeb already. Did that solve the problem? If not, please spend a little more time improving the original post with your findings. — JustLudo, Oct 12 '21 at 10:53
https://stackoverflow.com/questions/533905/get-the-cartesian-product-of-a-series-of-lists — wovano, Oct 12 '21 at 10:59

score 0 · Answer 1 · answered Oct 12 '21 at 11:02

0

You can create an array of tuples which corresponds to each unique link between the values in list1 and list2

linked_values=[]
for i in list1:
    for j in list2:
        linked_values.append((i,j))

answered Oct 12 '21 at 11:02

Trym Berg

score 0 · Answer 2 · answered Oct 12 '21 at 11:13

0

You could use the standard library function itertools.product() for this.

However, for trivial cases, you might as well use this one-liner:

output = [(i, j) for i in list1 for j in list2]

answered Oct 12 '21 at 11:13

wovano

2 Answers2