Sort two lists one string other float

Question

I have two lists

one = ['allen', 'steve', 'george', 'max']
two = [88.63, 33.99, 72.66, 92.11]

I would like two lists sorted as below.

one = ['max', 'allen', 'george', 'steve']
two = [92.11, 88.63, 72.66 33.99]

What I have tried

one, two = sorted(zip(one, two))

list `one` is not list of `str`. It's not even valid one, unless all elements are names, but not defined here. — buran, Oct 12 '21 at 15:48
why does max come before allen, but allen comes before george? — ph140, Oct 12 '21 at 15:52

score 0 · Answer 1 · edited Oct 12 '21 at 17:31

0

One way of doing that:

one, two = zip(*sorted(zip(one, two), key=lambda tup: tup[1], reverse=True))

edited Oct 12 '21 at 17:31

S.B

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answered Oct 12 '21 at 15:59

Dobos Imre

1

score 0 · Answer 2 · answered Oct 12 '21 at 16:00

You could combine the lists into a matrix and then sort the matrix using the numbers. The matrix is a 2D list that would group each number with a name. You can make this matrix using a list comprehension

combinedList = [[one[x], two[x]] for x in range(len(two))]

output:

[['max', 92.11], ['allen', 88.63], ['george', 72.66], ['steve', 33.99]]

Then, sort the list using the 2nd item in each entry (index 1)

outputList = sorted(combinedList, key=lambda x: x[1])

output:

[['steve', 33.99], ['george', 72.66], ['allen', 88.63], ['max', 92.11]]

For further processing, you could once again split this list back into list one and two, but sorted. Again, using list comprehension

one = [x[0] for x in outputList]
two = [x[1] for x in outputList]

output:

['steve', 'george', 'allen', 'max']
[33.99, 72.66, 88.63, 92.11]

Sort two lists one string other float

2 Answers2